∫ 01 ln( 1+2x3−2x )dx
Solution
The integral you've provided seems to be a bit complex and might involve advanced techniques of integration. However, the expression seems to be malformed. Could you please check and provide a correct version of the integral?
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l´ımx−→0ln(cos(3x))ln(cos(2x)) =ï 00ò= l´ımx−→0−3 sin(3x)cos(3x)−2 sin(2x)cos(2x)= l´ımx−→0−3 sin(3x) cos(2x)−2 sin(2x) cos(3x)=ï 00ò= 32 l´ımx−→03 cos(3x) cos(2x) − 2 sin(3x) sin(2x)2 cos(2x) cos(3x) − 3 sin(2x) sin(3x) = 32 · 32 = 94
Find ∫(2x2+ex) dx
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