To solve the integral ∫(2x²+eˣ) dx, we can separate it into two integrals:

∫2x² dx + ∫eˣ dx

1. Solve ∫2x² dx:

The antiderivative of x² is (1/3)x³. So, the integral of 2x² is (2/3)x³.

2. Solve ∫eˣ dx:

The antiderivative of eˣ is eˣ. So, the integral of eˣ is eˣ.

Therefore, the integral ∫(2x²+eˣ) dx is (2/3)x³ + eˣ + C, where C is the constant of integration.

Question

To solve the integral ∫(2x²+eˣ) dx, we can separate it into two integrals:

∫2x² dx + ∫eˣ dx

1. Solve ∫2x² dx:

The antiderivative of x² is (1/3)x³. So, the integral of 2x² is (2/3)x³.

2. Solve ∫eˣ dx:

The antiderivative of eˣ is eˣ. So, the integral of eˣ is eˣ.

Therefore, the integral ∫(2x²+eˣ) dx is (2/3)x³ + eˣ + C, where C is the constant of integration.

Knowee AI · Accepted Answer

To solve the integral ∫(2x²+eˣ) dx, we can separate it into two integrals:

∫2x² dx + ∫eˣ dx

1. Solve ∫2x² dx:

The antiderivative of x² is (1/3)x³. So, the integral of 2x² is (2/3)x³.

2. Solve ∫eˣ dx:

The antiderivative of eˣ is eˣ. So, the integral of eˣ is eˣ.

Therefore, the integral ∫(2x²+eˣ) dx is (2/3)x³ + eˣ + C, where C is the constant of integration.

Find ∫(2x2+ex) dx