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Amil, a curious coder, has a distinctive approach to handling numerical input. Write a program to get an integer from the user. If the number is even, the system employs a goto statement to a label indicating an affirmative response. Otherwise, another goto statement conveys a negative response.

Question

Amil, a curious coder, has a distinctive approach to handling numerical input. Write a program to get an integer from the user. If the number is even, the system employs a goto statement to a label indicating an affirmative response. Otherwise, another goto statement conveys a negative response.

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Solution

Here is a simple program in C language that follows the instructions:

#include <stdio.h>

int main() {
    int num;
    printf("Enter an integer: ");
    scanf("%d", &num);

    if (num % 2 == 0) {
        goto even;
    } else {
        goto odd;
    }

even:
    printf("Affirmative response. The number is even.");
    return 0;

odd:
    printf("Negative response. The number is odd.");
    return 0;
}

This program first asks the user to input an integer. It then checks if the number is even by using the modulus operator (%). If the number is even, it goes to the even label and prints an affirmative response. If the number is not even (i.e., it's odd), it goes to the odd label and prints a negative response.

This problem has been solved

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