Alice, an avid coder, utilizes the goto statement in her program. When she receives an input, if it's even, she employs goto to print its factors. Otherwise, she uses goto to display the next number of it. Write a program to achieve Alice's task.Input format :The input line consists of a single integer n, representing the number.Output format :If n is even:The first line displays "Even".The second line displays "Factors: " followed by the factors of n, separated by a space.If n is odd:The first line displays "Odd".The second line displays "Next number: " followed by the next number of n.Refer to the sample output for the formatting specifications.Code constraints :In the given scenario, the test cases fall under the following constraints:1 ≤ n ≤ 100Sample test cases :
Question
Alice, an avid coder, utilizes the goto statement in her program. When she receives an input, if it's even, she employs goto to print its factors. Otherwise, she uses goto to display the next number of it. Write a program to achieve Alice's task.Input format :The input line consists of a single integer n, representing the number.Output format :If n is even:The first line displays "Even".The second line displays "Factors: " followed by the factors of n, separated by a space.If n is odd:The first line displays "Odd".The second line displays "Next number: " followed by the next number of n.Refer to the sample output for the formatting specifications.Code constraints :In the given scenario, the test cases fall under the following constraints:1 ≤ n ≤ 100Sample test cases :
Solution
Here is a Python program that accomplishes Alice's task:
def print_factors(n):
print("Factors: ", end="")
for i in range(1, n + 1):
if n % i == 0:
print(i, end=" ")
def print_next(n):
print("Next number: " + str(n + 1))
n = int(input())
if n % 2 == 0:
print("Even")
print_factors(n)
else:
print("Odd")
print_next(n)
This program first defines two helper functions: print_factors(n) and print_next(n). print_factors(n) prints all factors of n by iterating from 1 to n and checking if n is divisible by the current number. print_next(n) simply prints the next number after n.
The main part of the program reads an integer n from the input. If n is even, it prints "Even" and calls print_factors(n). If n is odd, it prints "Odd" and calls print_next(n).
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