A free-diver is training to dive deeper. They can currently dive to −12m⁡−12m. After 66 months they can dive 44 times deeper. Choose two equations that represent this scenario, where 𝑥x is the new depth the diver can reach.𝑥=4×−12x=4×−12𝑥=−124x= 4−12​ 𝑥4=−124x​ =−124𝑥=−124x=−12

Instructions: For the following real-world problem, solve using any method. Use what you’ve learned to determine which method would be best. Put your answer in the context of the problem and determine the appropriate final answer.Jessica is practicing her dives off the diving board. When she dives into the water, the path her body makes and where she resurfaces can be modeled by the equation 0=x2−6x0=𝑥2−6𝑥 where x𝑥 is the number of horizontal feet she travels. Solve the equation to find the number of feet she will travel before coming back to the surface of the water.The two solutions to the equation are: x=𝑥= or Which of your solutions gives the horizontal distance Jessica has traveled when she returns to the surface? x=𝑥= feet

(08.02 MC)The function f(x) = −x2 − 9x + 10 shows the relationship between the vertical distance of a diver from a pool's surface f(x), in feet, and the horizontal distance x, in feet, of a diver from the diving board. What is a zero of f(x), and what does it represent?Group of answer choicesx = 1; the diver jumps in the pool at 1 foot per secondx = 10; the diver jumps in the pool at 10 feet per secondx = 1; the diver hits the water 1 foot away horizontally from the boardx = 10; the diver hits the water 10 feet away horizontally from the board

A diver needs to descend to a depth of 100 feet. She wants to do it in 5 equal descents.(i) Use the number line to find how far the diver should travel in each of the 5 descents.(ii) To solve this problem, you can set up a division problem: _____.

We know that standard pressure is one atmosphere, or 760 millimeters of mercury. This pressure results from the weight of gas molecules in the atmosphere. A diver entering the water is subject to both water pressure and air pressure. Because water is much denser than air, the pressure increases rapidly as the diver descends. At the depth of 34 feet in fresh water, the diver is experiencing 2 atmospheres of pressure (one from air pressure and one from the 34 feet of water). For every additional 34 feet the diver descends, he will be under an additional atmosphere of pressure.Since water pressure is proportional to depth, how many atmospheres of pressure would a diver experience at 102 feet? Why wouldn't this pressure squash the diver? Answering this second question may be easier if you think of the reason a person on land is not squashed by one atmosphere of pressure. Explain your answer in detail.

Jamieson is competing in his school’s 3.0-metre diving competition. For his last dive, he is performing a forward somersault. The duration of the dive must be exactly 1.75 seconds or he will under- or over-rotate before hitting the water. He jumps upwards off the board with a vertical velocity of 6.0 m s−1 and takes $t$t​ seconds to land in the pool. Take the upwards direction as positive.Which of the following correctly describes the displacement of the diver as he hits the water?A0 mB3.0 mC−3.0 mD6.0 m