A capacitor is connected across an oscillating emf with a peak current through the capacitor of 3.50 A. If the frequency ω𝜔 is tripled, what is the peak current? 3.50 A 2.02 A 10.5 A 1.17 A
Question
A capacitor is connected across an oscillating emf with a peak current through the capacitor of 3.50 A. If the frequency ω𝜔 is tripled, what is the peak current? 3.50 A 2.02 A 10.5 A 1.17 A
Solution
The current in a capacitor connected to an AC source is given by the equation I = VωC, where I is the current, V is the voltage, ω is the angular frequency, and C is the capacitance.
From this equation, we can see that the current is directly proportional to the frequency. This means that if the frequency is tripled, the current will also be tripled.
Therefore, if the initial peak current was 3.50 A, when the frequency is tripled, the peak current will be 3.50 A * 3 = 10.5 A. So, the correct answer is 10.5 A.
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