.A vehicle of mass 120 kg is moving with a uniform velocity of 108km/h . The force required to stop the vehicle in 10 s is

Step 1: Convert the velocity from km/h to m/s The conversion factor is 1 km/h = 5/18 m/s. So, 108 km/h = 108 * (5/18) = 30 m/s.

Step 2: Use the formula for force The formula for force is F = ma, where F is the force, m is the mass, and a is the acceleration.

Step 3: Find the acceleration The acceleration is the change in velocity divided by the change in time. In this case, the vehicle is stopping, so the final velocity is 0. The initial velocity is 30 m/s, and the time is 10 s. So, the acceleration is (0 - 30 m/s) / 10 s = -3 m/s^2. The negative sign indicates that this is a deceleration.

Step 4: Substitute the mass and acceleration into the formula for force F = (120 kg) * (-3 m/s^2) = -360 N. The negative sign indicates that the force is acting in the opposite direction of the motion of the vehicle, which makes sense because the force is stopping the vehicle.

So, the force required to stop the vehicle in 10 s is 360 N.