The problem involves the physics concept of work and energy. The work done by the force to stop the car is equal to the change in kinetic energy of the car.

First, let's calculate the work done to stop the car when it's moving at 10 m/s.

The kinetic energy of the car when it's moving at 10 m/s is given by the formula:

KE1 = 1/2 * m * v1^2

where m is the mass of the car and v1 is the initial velocity (10 m/s).

The work done by the force to stop the car is equal to the change in kinetic energy, which is KE1 - 0 (since the final kinetic energy is 0 when the car is stopped).

So, Work1 = KE1 = 1/2 * m * (10 m/s)^2

The work done by the force is also equal to the force times the distance over which it is applied. So,

Work1 = F * d1

where F is the force and d1 is the distance (20 m).

Setting these two expressions for Work1 equal to each other gives:

1/2 * m * (10 m/s)^2 = F * 20 m

Now, let's calculate the distance needed to stop the car when it's moving at 30 m/s.

The kinetic energy of the car when it's moving at 30 m/s is given by the formula:

KE2 = 1/2 * m * v2^2

where v2 is the initial velocity (30 m/s).

The work done by the force to stop the car is equal to the change in kinetic energy, which is KE2 - 0.

So, Work2 = KE2 = 1/2 * m * (30 m/s)^2

The work done by the force is also equal to the force times the distance over which it is applied. So,

Work2 = F * d2

where d2 is the distance we want to find.

Setting these two expressions for Work2 equal to each other gives:

1/2 * m * (30 m/s)^2 = F * d2

We can solve this equation for d2 by substituting the expression for F from the first equation:

1/2 * m * (30 m/s)^2 = (1/2 * m * (10 m/s)^2 / 20 m) * d2

Solving this equation for d2 gives:

d2 = (30 m/s)^2 / (10 m/s)^2 * 20 m = 180 m

So, the car can be stopped by this force in a distance of 180 m when it's moving at 30 m/s.

Question

The problem involves the physics concept of work and energy. The work done by the force to stop the car is equal to the change in kinetic energy of the car.

First, let's calculate the work done to stop the car when it's moving at 10 m/s.

The kinetic energy of the car when it's moving at 10 m/s is given by the formula:

KE1 = 1/2 * m * v1^2

where m is the mass of the car and v1 is the initial velocity (10 m/s).

The work done by the force to stop the car is equal to the change in kinetic energy, which is KE1 - 0 (since the final kinetic energy is 0 when the car is stopped).

So, Work1 = KE1 = 1/2 * m * (10 m/s)^2

The work done by the force is also equal to the force times the distance over which it is applied. So,

Work1 = F * d1

where F is the force and d1 is the distance (20 m).

Setting these two expressions for Work1 equal to each other gives:

1/2 * m * (10 m/s)^2 = F * 20 m

Now, let's calculate the distance needed to stop the car when it's moving at 30 m/s.

The kinetic energy of the car when it's moving at 30 m/s is given by the formula:

KE2 = 1/2 * m * v2^2

where v2 is the initial velocity (30 m/s).

The work done by the force to stop the car is equal to the change in kinetic energy, which is KE2 - 0.

So, Work2 = KE2 = 1/2 * m * (30 m/s)^2

The work done by the force is also equal to the force times the distance over which it is applied. So,

Work2 = F * d2

where d2 is the distance we want to find.

Setting these two expressions for Work2 equal to each other gives:

1/2 * m * (30 m/s)^2 = F * d2

We can solve this equation for d2 by substituting the expression for F from the first equation:

1/2 * m * (30 m/s)^2 = (1/2 * m * (10 m/s)^2 / 20 m) * d2

Solving this equation for d2 gives:

d2 = (30 m/s)^2 / (10 m/s)^2 * 20 m = 180 m

So, the car can be stopped by this force in a distance of 180 m when it's moving at 30 m/s.

Knowee AI · Accepted Answer

The problem involves the physics concept of work and energy. The work done by the force to stop the car is equal to the change in kinetic energy of the car.

First, let's calculate the work done to stop the car when it's moving at 10 m/s.

The kinetic energy of the car when it's moving at 10 m/s is given by the formula:

KE1 = 1/2 * m * v1^2

where m is the mass of the car and v1 is the initial velocity (10 m/s).

The work done by the force to stop the car is equal to the change in kinetic energy, which is KE1 - 0 (since the final kinetic energy is 0 when the car is stopped).

So, Work1 = KE1 = 1/2 * m * (10 m/s)^2

The work done by the force is also equal to the force times the distance over which it is applied. So,

Work1 = F * d1

where F is the force and d1 is the distance (20 m).

Setting these two expressions for Work1 equal to each other gives:

1/2 * m * (10 m/s)^2 = F * 20 m

Now, let's calculate the distance needed to stop the car when it's moving at 30 m/s.

The kinetic energy of the car when it's moving at 30 m/s is given by the formula:

KE2 = 1/2 * m * v2^2

where v2 is the initial velocity (30 m/s).

The work done by the force to stop the car is equal to the change in kinetic energy, which is KE2 - 0.

So, Work2 = KE2 = 1/2 * m * (30 m/s)^2

The work done by the force is also equal to the force times the distance over which it is applied. So,

Work2 = F * d2

where d2 is the distance we want to find.

Setting these two expressions for Work2 equal to each other gives:

1/2 * m * (30 m/s)^2 = F * d2

We can solve this equation for d2 by substituting the expression for F from the first equation:

1/2 * m * (30 m/s)^2 = (1/2 * m * (10 m/s)^2 / 20 m) * d2

Solving this equation for d2 gives:

d2 = (30 m/s)^2 / (10 m/s)^2 * 20 m = 180 m

So, the car can be stopped by this force in a distance of 180 m when it's moving at 30 m/s.

A car moving with a velocity 10m/s can be stopped by the application of a constant force F in a distance of 20m. If the velocity of the car is 30m/s. If can be stopped by this force in

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