Calculate the mass of 1.50 moles of lead (II) nitrate.SHOW ALL STEPS FOR FULL MARKS

Step 1: Determine the molar mass of lead (II) nitrate (Pb(NO3)2)

The molar mass of a compound is calculated by adding up the molar mass of each of its constituent atoms, multiplied by the number of times they appear in the compound.

• The molar mass of lead (Pb) is approximately 207.2 g/mol.
• The molar mass of nitrogen (N) is approximately 14.01 g/mol.
• The molar mass of oxygen (O) is approximately 16.00 g/mol.

In lead (II) nitrate, there is 1 atom of lead, 2 atoms of nitrogen, and 6 atoms of oxygen.

So, the molar mass of lead (II) nitrate is:

(1 x 207.2 g/mol) + (2 x 14.01 g/mol) + (6 x 16.00 g/mol) = 331.22 g/mol

Step 2: Calculate the mass of 1.50 moles of lead (II) nitrate

Now that we know the molar mass of lead (II) nitrate, we can calculate the mass of 1.50 moles of it.

Mass = Moles x Molar mass

So, the mass of 1.50 moles of lead (II) nitrate is:

1.50 moles x 331.22 g/mol = 496.83 g

Therefore, the mass of 1.50 moles of lead (II) nitrate is 496.83 grams.