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Lead(II) nitrate is a poisonous substance which has been used in the manufacture of special explosives and as a sensitizer in photography. Calculate the mass of lead in 139 g of Pb(NO3)2Group of answer choices87.0 g90.8 g83.4 g107 g

Question

Lead(II) nitrate is a poisonous substance which has been used in the manufacture of special explosives and as a sensitizer in photography. Calculate the mass of lead in 139 g of Pb(NO3)2Group of answer choices87.0 g90.8 g83.4 g107 g

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Solution

To calculate the mass of lead in 139 g of Pb(NO3)2, you need to know the molar mass of Pb(NO3)2 and the molar mass of Pb.

  1. Calculate the molar mass of Pb(NO3)2: The molar mass of Pb is approximately 207.2 g/mol. The molar mass of N is approximately 14.01 g/mol. The molar mass of O is approximately 16.00 g/mol.

    Pb(NO3)2 has 1 atom of Pb, 2 atoms of N, and 6 atoms of O. So, the molar mass of Pb(NO3)2 = (1207.2 g/mol) + (214.01 g/mol) + (6*16.00 g/mol) = 331.22 g/mol.

  2. Calculate the mass of Pb in 139 g of Pb(NO3)2: The proportion of Pb in Pb(NO3)2 is (207.2 g/mol) / (331.22 g/mol) = 0.6255.

    Therefore, the mass of Pb in 139 g of Pb(NO3)2 = 0.6255 * 139 g = 86.96 g.

So, the mass of lead in 139 g of Pb(NO3)2 is approximately 87.0 g.

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