To solve this problem, we will use the formula for permutations of multiset: n! / (r1! * r2! * ... * rk!), where n is the total number of items, and r1, r2, ..., rk are the numbers of each type of item.

In the word REPERTOIRE, there are 10 letters in total.

1. There are 3 Rs.
2. There are 3 Es.
3. There is 1 P.
4. There is 1 T.
5. There is 1 O.
6. There is 1 I.

So, the number of distinct arrangements of the letters in REPERTOIRE is:

10! / (3! * 3! * 1! * 1! * 1! * 1!) = 3,628,800 / (6 * 6 * 1 * 1 * 1 * 1) = 101,200.

Question

To solve this problem, we will use the formula for permutations of multiset: n! / (r1! * r2! * ... * rk!), where n is the total number of items, and r1, r2, ..., rk are the numbers of each type of item.

In the word REPERTOIRE, there are 10 letters in total.

1. There are 3 Rs.
2. There are 3 Es.
3. There is 1 P.
4. There is 1 T.
5. There is 1 O.
6. There is 1 I.

So, the number of distinct arrangements of the letters in REPERTOIRE is:

10! / (3! * 3! * 1! * 1! * 1! * 1!) = 3,628,800 / (6 * 6 * 1 * 1 * 1 * 1) = 101,200.

Knowee AI · Accepted Answer

To solve this problem, we will use the formula for permutations of multiset: n! / (r1! * r2! * ... * rk!), where n is the total number of items, and r1, r2, ..., rk are the numbers of each type of item.

In the word REPERTOIRE, there are 10 letters in total.

1. There are 3 Rs.
2. There are 3 Es.
3. There is 1 P.
4. There is 1 T.
5. There is 1 O.
6. There is 1 I.

So, the number of distinct arrangements of the letters in REPERTOIRE is:

10! / (3! * 3! * 1! * 1! * 1! * 1!) = 3,628,800 / (6 * 6 * 1 * 1 * 1 * 1) = 101,200.

Find the number of distinct arrangements of the 10 letters in REPERTOIRE.Two of the same letter are considered identical (not distinct).

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