To solve this problem, we use the formula for permutations of multiset: n! / (r1! * r2! * ... * rk!), where n is the total number of items, and r1, r2, ..., rk are the numbers of each type of item.

In the word BEGINNING, there are 9 letters in total.

1. There are 3 N's.
2. There are 2 G's.
3. There is 1 B.
4. There is 1 E.
5. There is 1 I.
6. There is 1 I.

So, the number of distinct arrangements of the letters in BEGINNING is:

9! / (3! * 2! * 1! * 1! * 1! * 1!) = 362,880 / (6 * 2 * 1 * 1 * 1 * 1) = 30,240.

Question

To solve this problem, we use the formula for permutations of multiset: n! / (r1! * r2! * ... * rk!), where n is the total number of items, and r1, r2, ..., rk are the numbers of each type of item.

In the word BEGINNING, there are 9 letters in total.

1. There are 3 N's.
2. There are 2 G's.
3. There is 1 B.
4. There is 1 E.
5. There is 1 I.
6. There is 1 I.

So, the number of distinct arrangements of the letters in BEGINNING is:

9! / (3! * 2! * 1! * 1! * 1! * 1!) = 362,880 / (6 * 2 * 1 * 1 * 1 * 1) = 30,240.

Knowee AI · Accepted Answer

To solve this problem, we use the formula for permutations of multiset: n! / (r1! * r2! * ... * rk!), where n is the total number of items, and r1, r2, ..., rk are the numbers of each type of item.

In the word BEGINNING, there are 9 letters in total.

1. There are 3 N's.
2. There are 2 G's.
3. There is 1 B.
4. There is 1 E.
5. There is 1 I.
6. There is 1 I.

So, the number of distinct arrangements of the letters in BEGINNING is:

9! / (3! * 2! * 1! * 1! * 1! * 1!) = 362,880 / (6 * 2 * 1 * 1 * 1 * 1) = 30,240.

Find the number of distinct arrangements of the 9 letters in BEGINNING.Two of the same letter are considered identical (not distinct).

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