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Consider a 20 kg uniform circular disk of radius 0.2 m. It is pin supported at its center and is at rest initially. The disk is acted upon by a constant force F = 20 N through a massless string wrapped around its periphery as shown in the figure. Suppose the disk makes n number of revolutions to attain an angular speed of 50 rad s–1. The value of n, to the nearest integer, is _______. [Given : In one complete revolution, the disk rotates by 6.28 rad]

Question

Consider a 20 kg uniform circular disk of radius 0.2 m. It is pin supported at its center and is at rest initially. The disk is acted upon by a constant force F = 20 N through a massless string wrapped around its periphery as shown in the figure. Suppose the disk makes n number of revolutions to attain an angular speed of 50 rad s–1. The value of n, to the nearest integer, is _______. [Given : In one complete revolution, the disk rotates by 6.28 rad]

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Solution

To solve this problem, we need to use the principles of rotational motion.

First, we need to calculate the torque (τ) produced by the force. Torque is given by the formula τ = F*r, where F is the force and r is the radius of the disk.

τ = 20 N * 0.2 m = 4 Nm

Next, we need to calculate the moment of inertia (I) of the disk. For a uniform circular disk, the moment of inertia is given by the formula I = 0.5mr^2, where m is the mass of the disk and r is its radius.

I = 0.5 * 20 kg * (0.2 m)^2 = 0.4 kg*m^2

Now, we can use the relation between torque, moment of inertia, and angular acceleration (α), which is given by the formula τ = I*α. Solving for α, we get:

α = τ / I = 4 Nm / 0.4 kg*m^2 = 10 rad/s^2

The final angular speed (ω) is given as 50 rad/s. The initial angular speed (ω0) is 0 rad/s (since the disk is initially at rest). We can use the formula ω = ω0 + α*t to find the time (t) it takes for the disk to reach the final angular speed.

50 rad/s = 0 rad/s + 10 rad/s^2 * t

Solving for t, we get t = 5 s.

Finally, we can calculate the number of revolutions (n) the disk makes in this time. The angular displacement (θ) is given by the formula θ = ω0t + 0.5α*t^2. Substituting the known values, we get:

θ = 0 rad/s * 5 s + 0.5 * 10 rad/s^2 * (5 s)^2 = 125 rad

Since one complete revolution corresponds to 6.28 rad, the number of revolutions is given by n = θ / 6.28.

n = 125 rad / 6.28 rad/revolution ≈ 20 revolutions

So, to the nearest integer, the disk makes 20 revolutions to attain an angular speed of 50 rad/s.

This problem has been solved

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