An ideal gas expands from 10−3m3 to 10-2m3 at 300 K, against a constant pressure of 105Nm−2 . The work done on it is
Question
An ideal gas expands from 10−3m3 to 10-2m3 at 300 K, against a constant pressure of 105Nm−2 . The work done on it is
Solution
The work done on an ideal gas can be calculated using the formula:
W = P * ΔV
where: W is the work done, P is the pressure, and ΔV is the change in volume.
Given: P = 10^5 N/m^2, Initial volume (V1) = 10^-3 m^3, Final volume (V2) = 10^-2 m^3.
We can calculate ΔV as follows: ΔV = V2 - V1 ΔV = 10^-2 m^3 - 10^-3 m^3 ΔV = 9 * 10^-3 m^3
Now we can calculate the work done: W = P * ΔV W = 10^5 N/m^2 * 9 * 10^-3 m^3 W = 900 Joules
So, the work done on the gas is 900 Joules.
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