A gas expands from 10L to 100L against an external pressure of 2 atom. The work is
Question
A gas expands from 10L to 100L against an external pressure of 2 atom. The work is
Solution
The work done by a gas during expansion or compression can be calculated using the formula:
W = -PΔV
where: W is the work done, P is the external pressure, and ΔV is the change in volume.
In this case, the gas expands from 10L to 100L, so the change in volume ΔV is 100L - 10L = 90L.
The external pressure P is given as 2 atm. However, to calculate work, we need to convert this pressure to a more appropriate unit. The conversion factor is 1 atm = 101.3 J/L. So, the pressure in these units is 2 atm * 101.3 J/L/atm = 202.6 J/L.
Substituting these values into the formula gives:
W = -202.6 J/L * 90L = -18234 J
The negative sign indicates that the work is done by the gas on the surroundings. Therefore, the work done by the gas is -18234 Joules.
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