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list_sort function Sorts the argument input list (nums) in descending orderuser_code.py123def list_sort(nums): # write some code here passRestore original fileSave onlySave & Grade Unlimited attempts

Question

list_sort function Sorts the argument input list (nums) in descending orderuser_code.py123def list_sort(nums): # write some code here passRestore original fileSave onlySave & Grade Unlimited attempts

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Solution

Here is a step-by-step solution to create a function list_sort that sorts a list in descending order:

  1. Define the function list_sort that takes one argument, nums, which is the list to be sorted.
def list_sort(nums):
  1. Use the sort() method of the list to sort the list in ascending order. The sort() method sorts the list in-place, meaning that it modifies the original list.
def list_sort(nums):
    nums.sort()
  1. To sort the list in descending order, pass the argument reverse=True to the sort() method. This will sort the list in the reverse of the natural order, which is descending order for numbers.
def list_sort(nums):
    nums.sort(reverse=True)
  1. Since the sort() method sorts the list in-place, you don't need to return anything from the function. The original list will be sorted when the function is done.
def list_sort(nums):
    nums.sort(reverse=True)

You can use this function to sort a list of numbers in descending order like this:

numbers = [5, 1, 9, 3, 7]
list_sort(numbers)
print(numbers)  # Output: [9, 7, 5, 3, 1]

This will print the list [9, 7, 5, 3, 1], which is the list numbers sorted in descending order.

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Similar Questions

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