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Define a function sort_grades(tup1). The argument tup1 is a tuple each composed of (student_name, score). The function returns a tuple with same elements of tup1 but sorted by their scores in descending order.Exampletup1 = (('Bob', 47), ('Claire', 61), ('Dominic', 79))Expected output:(('Dominic', 79), ('Claire', 61), ('Bob', 47))Hintfirst convert tup1 to a list. Since each element in this list is a tuple with two items (student_name, score), to sort the list according to the second item score, you can use Python built-in sorted function:sorted(iterable, key=None, reverse=False) function returns a sorted list from the iterable object(refer to similar examples in Chapter 4.1).convert the above list to a tuple again, and return the tuple

Question

Define a function sort_grades(tup1). The argument tup1 is a tuple each composed of (student_name, score). The function returns a tuple with same elements of tup1 but sorted by their scores in descending order.Exampletup1 = (('Bob', 47), ('Claire', 61), ('Dominic', 79))Expected output:(('Dominic', 79), ('Claire', 61), ('Bob', 47))Hintfirst convert tup1 to a list. Since each element in this list is a tuple with two items (student_name, score), to sort the list according to the second item score, you can use Python built-in sorted function:sorted(iterable, key=None, reverse=False) function returns a sorted list from the iterable object(refer to similar examples in Chapter 4.1).convert the above list to a tuple again, and return the tuple

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Solution

Sure, here is a step-by-step guide on how to define the function sort_grades(tup1):

  1. First, you need to convert the tuple tup1 to a list. This is because tuples in Python are immutable, meaning they cannot be changed once created. On the other hand, lists are mutable and can be sorted. You can convert the tuple to a list by using the list() function. Let's call this list list1. Here is how you can do it:
list1 = list(tup1)
  1. Next, you need to sort list1 according to the scores. You can use the built-in sorted() function in Python. The sorted() function takes three parameters: iterable, key and reverse.

    • iterable is the sequence (string, tuple, etc.) or collection (set, dictionary, etc.) or an iterator object to be sorted.
    • key is a function that serves as a key or a basis of sort comparison.
    • reverse is a boolean value. If set to True, then the iterable would be sorted in reverse (descending) order.

    In your case, iterable is list1, key should be a function that returns the second element of the tuple (i.e., the score), and reverse should be True because you want to sort the scores in descending order. Here is how you can do it:

list1 = sorted(list1, key=lambda x: x[1], reverse=True)
  1. Finally, you need to convert list1 back to a tuple and return it. You can convert the list to a tuple by using the tuple() function. Here is how you can do it:
return tuple(list1)

So, the complete function sort_grades(tup1) would look like this:

def sort_grades(tup1):
    list1 = list(tup1)
    list1 = sorted(list1, key=lambda x: x[1], reverse=True)
    return tuple(list1)

You can test this function with your example:

tup1 = (('Bob', 47), ('Claire', 61), ('Dominic', 79))
print(sort_grades(tup1))  # prints (('Dominic', 79), ('Claire', 61), ('Bob', 47))

This problem has been solved

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Given 3 tables, students(id, name) , courses(id, name) , grades(id, course_id, student_id, grade), find the top 100 students based on their average grades sorted descendingly by the average grade and in case multiple students have the same average grade, sort them lexicographically in ascending order by their names. Your query should output a table with the following columns (name, average_grade).

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