The truth value of (r∧r)∧r is false. Here's the step by step explanation:

1. The symbol '∧' stands for logical conjunction (AND). The result of 'r ∧ r' is true if and only if both 'r' are true.

2. Given that 'r' is false, 'r ∧ r' is also false because both are not true.

3. Now, we have to find the truth value of 'false ∧ r' (which is the result of the first operation and the remaining 'r').

4. Again, the result of 'false ∧ r' is true if and only if both are true. But we know that 'r' is false.

5. Therefore, 'false ∧ r' is also false.

So, the truth value of (r∧r)∧r is false when r is false.

Question

The truth value of (r∧r)∧r is false. Here's the step by step explanation:

1. The symbol '∧' stands for logical conjunction (AND). The result of 'r ∧ r' is true if and only if both 'r' are true.

2. Given that 'r' is false, 'r ∧ r' is also false because both are not true.

3. Now, we have to find the truth value of 'false ∧ r' (which is the result of the first operation and the remaining 'r').

4. Again, the result of 'false ∧ r' is true if and only if both are true. But we know that 'r' is false.

5. Therefore, 'false ∧ r' is also false.

So, the truth value of (r∧r)∧r is false when r is false.

Knowee AI · Accepted Answer

The truth value of (r∧r)∧r is false. Here's the step by step explanation:

1. The symbol '∧' stands for logical conjunction (AND). The result of 'r ∧ r' is true if and only if both 'r' are true.

2. Given that 'r' is false, 'r ∧ r' is also false because both are not true.

3. Now, we have to find the truth value of 'false ∧ r' (which is the result of the first operation and the remaining 'r').

4. Again, the result of 'false ∧ r' is true if and only if both are true. But we know that 'r' is false.

5. Therefore, 'false ∧ r' is also false.

So, the truth value of (r∧r)∧r is false when r is false.

If r is false, what is the truth value of (r∧r)∧r?