If q is true, r is true and s is false, what is the truth value of ~(q∧s)∧r?

To solve this problem, we need to break it down into smaller parts and solve each part step by step.

1. First, let's look at the part inside the parentheses: q∧s. The symbol ∧ stands for "and", so q∧s means "q and s". We know that q is true and s is false. In an "and" statement, both parts must be true for the whole statement to be true. Since s is false, q∧s is also false.

2. Next, let's look at the ~ symbol. This stands for "not", so ~q∧s means "not (q and s)". We've already determined that q∧s is false, so ~q∧s is the opposite of that, which is true.

3. Finally, let's look at the whole statement: ~(q∧s)∧r. This means "(not (q and s)) and r". We've already determined that ~(q∧s) is true, and we know that r is true. In an "and" statement, both parts must be true for the whole statement to be true. Since both parts are true, the whole statement is true.

So, the truth value of ~(q∧s)∧r is true.