A student releases a ball from rest on an inclined plane and measures that it travels a distance of 0.5 m in a time of 2.0 s. The acceleration of the ball isGroup of answer choices0.125 m/s2.0.5 m/s2.1.0 m/s2.0.25 m/s2.
Question
A student releases a ball from rest on an inclined plane and measures that it travels a distance of 0.5 m in a time of 2.0 s. The acceleration of the ball isGroup of answer choices0.125 m/s2.0.5 m/s2.1.0 m/s2.0.25 m/s2.
Solution
The acceleration of the ball can be calculated using the equation of motion:
s = ut + 0.5at^2
where: s = distance travelled = 0.5 m u = initial velocity = 0 (since the ball is released from rest) t = time = 2.0 s a = acceleration (which we are trying to find)
Substituting the given values into the equation, we get:
0.5 = 02 + 0.5a*(2^2)
Solving for a, we get:
a = (2*0.5) / (2^2) = 0.5 m/s^2
So, the acceleration of the ball is 0.5 m/s^2.
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