To solve this problem, we can use the equation of motion that relates distance (d), initial velocity (v0), acceleration (a), and time (t):

d = v0*t + 0.5*a*t^2

In this case, the ball starts from rest, so the initial velocity v0 is 0. The distance d is 40.0 meters and the acceleration a is 5.0 meters per second^2. We can plug these values into the equation and solve for time t:

40.0 = 0*t + 0.5*5.0*t^2
40.0 = 2.5*t^2
t^2 = 40.0 / 2.5
t^2 = 16
t = sqrt(16)
t = 4.0 seconds

So, the correct answer is B, 4.0 seconds.

Question

To solve this problem, we can use the equation of motion that relates distance (d), initial velocity (v0), acceleration (a), and time (t):

d = v0*t + 0.5*a*t^2

In this case, the ball starts from rest, so the initial velocity v0 is 0. The distance d is 40.0 meters and the acceleration a is 5.0 meters per second^2. We can plug these values into the equation and solve for time t:

40.0 = 0*t + 0.5*5.0*t^2
40.0 = 2.5*t^2
t^2 = 40.0 / 2.5
t^2 = 16
t = sqrt(16)
t = 4.0 seconds

So, the correct answer is B, 4.0 seconds.

Knowee AI · Accepted Answer

To solve this problem, we can use the equation of motion that relates distance (d), initial velocity (v0), acceleration (a), and time (t):

d = v0*t + 0.5*a*t^2

In this case, the ball starts from rest, so the initial velocity v0 is 0. The distance d is 40.0 meters and the acceleration a is 5.0 meters per second^2. We can plug these values into the equation and solve for time t:

40.0 = 0*t + 0.5*5.0*t^2
40.0 = 2.5*t^2
t^2 = 40.0 / 2.5
t^2 = 16
t = sqrt(16)
t = 4.0 seconds

So, the correct answer is B, 4.0 seconds.

A ball starting from rest accelerates uniformly at 5.0 meters per second2 as it rolls 40.0 meters down an incline. How much time is required for the ball to roll the 40.0 meters?A 2.8 sB 4.0 sC 8.0 sD 16 s

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