.A block of weight 50N is moving over a horizontal surface starting at rest, moves (7)over a distance of 25m in l0 seconds under the action of a force of 20N. Determinethe coefficient of friction between the surfaces.18a䐀漀眀渀氀漀愀搀攀搀 昀爀漀洀 䬀琀甀渀漀琀攀猀⸀椀渀
Question
.A block of weight 50N is moving over a horizontal surface starting at rest, moves (7)over a distance of 25m in l0 seconds under the action of a force of 20N. Determinethe coefficient of friction between the surfaces.18a䐀漀眀渀氀漀愀搀攀搀 昀爀漀洀 䬀琀甀渀漀琀攀猀⸀椀渀
Solution
To determine the coefficient of friction between the surfaces, we can use the equation:
Frictional force = Normal force * Coefficient of friction
Given that the weight of the block is 50N and the force applied is 20N, we can calculate the normal force:
Normal force = Weight - Applied force Normal force = 50N - 20N Normal force = 30N
Next, we need to calculate the acceleration of the block using the distance and time given:
Acceleration = (Final velocity - Initial velocity) / Time Acceleration = (0 - 0) / 10s Acceleration = 0 m/s^2
Since the block is moving at a constant velocity, the net force acting on it is zero. Therefore, the frictional force is equal in magnitude and opposite in direction to the applied force:
Frictional force = Applied force Frictional force = 20N
Now we can substitute the values into the equation to find the coefficient of friction:
Frictional force = Normal force * Coefficient of friction 20N = 30N * Coefficient of friction
Simplifying the equation:
Coefficient of friction = 20N / 30N Coefficient of friction = 0.67
Therefore, the coefficient of friction between the surfaces is 0.67.
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