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Problem Statement:Round off the given floating point value with accurate to 2 decimal places.Input Format:Accept a floating point valueOutput Format:Print the value accurate to 2 decimal placesConstraints:3.4E-4932 <= inp <= 1.1E+4932Sample Input 1:-165.12859Sample Output 1:-165.13Sample Input 2:12.53412Sample Output 2:12.53

Question

Problem Statement:Round off the given floating point value with accurate to 2 decimal places.Input Format:Accept a floating point valueOutput Format:Print the value accurate to 2 decimal placesConstraints:3.4E-4932 <= inp <= 1.1E+4932Sample Input 1:-165.12859Sample Output 1:-165.13Sample Input 2:12.53412Sample Output 2:12.53

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Solution

This problem is asking for a program that can round off a given floating point number to 2 decimal places.

Here is a step-by-step solution in Python:

  1. First, we need to accept a floating point value. We can do this using the input() function in Python, which reads a line from input, converts it to a string, and returns that string. We also need to convert this string to a float, so we use the float() function. Here is how you can do it:
inp = float(input())
  1. Next, we need to round off this floating point value to 2 decimal places. We can do this using the round() function in Python, which returns a floating point number that is a rounded version of the specified number, with the specified number of decimals. The first parameter is the number to be rounded, and the second parameter is the number of decimals. Here is how you can do it:
rounded_value = round(inp, 2)
  1. Finally, we need to print this rounded value. We can do

This problem has been solved

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