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Accept a floating point  value and precision value and print the floating point  value according to the precision given.Input Format:Accept one floating point  and one integer valueOutput Format:print the floating point value according to the given precision

Question

Accept a floating point  value and precision value and print the floating point  value according to the precision given.Input Format:Accept one floating point  and one integer valueOutput Format:print the floating point value according to the given precision

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Solution

Sure, here is a step by step guide on how to solve this problem in Python:

Step 1: Accept a floating point value from the user. You can use the input() function in Python to accept user input. Since input() function returns a string, you need to convert the input to a floating point number using the float() function.

float_value = float(input("Enter a floating point value: "))

Step 2: Accept an integer value from the user. This will be the precision value. Again, use the input() function to accept user input and the int() function to convert the input to an integer.

precision = int(input("Enter the precision value: "))

Step 3: Print the floating point value according to the given precision. You can use the format() function in Python to format the floating point number to the desired precision.

print("{0:.{1}f}".format(float_value, precision))

In the format() function, {0} is the placeholder for float_value and {1} is the placeholder for precision. The :.{1}f inside the curly braces is the format specification for the floating point number. The . indicates that the number should be printed with a decimal point, {1} specifies the precision, and f indicates that the number is a floating point number.

Here is the complete code:

float_value = float(input("Enter a floating point value: "))
precision = int(input("Enter the precision value: "))
print("{0:.{1}f}".format(float_value, precision))

This code will print the floating point value according to the given precision.

This problem has been solved

Similar Questions

Problem Statement:Accept a floating point  value and precision value and print the floating point  value according to the precision given.Input Format:Accept one floating point  and one integer valueOutput Format:print the floating point value according to the given precisionConstraints:3.4E-4932 to 1.1E+4932Sample Input :15.87 6Sample Output :15.870000

Problem Statement:Round off the given floating point value with accurate to 2 decimal places.Input Format:Accept a floating point valueOutput Format:Print the value accurate to 2 decimal placesConstraints:3.4E-4932 <= inp <= 1.1E+4932Sample Input 1:-165.12859Sample Output 1:-165.13Sample Input 2:12.53412Sample Output 2:12.53

Problem Statement:Display the given floating point value to its nearest integer valueInput Format:Accept a floating point value as input.Output Format:Print the nearest integer valueConstraints:3.4E-4932 <= inp <= 1.1E+4932Sample Input 1:159.357Sample Output 1:159Sample Input 2:15.9

Complete the source code in order to print the float stored in the variable number with a precision of 2 digits.

Represent the following as a single precision floating point (IEEE 754) number:a) 85.125b) -4.75

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