public interface Deduction { static void deduct() { System.out.println("deduct"); }}public class Customer implements Deduction { public static void deduct() { System.out.println("deduction for customer"); }}public class TechSol { public static void main(String[] args) { Deduction deduction = new Customer(); deduction.deduct(); }}What will happen when the code is subjected to compilation and execution? The code will not get compiled as the static method of interface is not accessed using interface nameWill get executed successfully leaving the output “deduct”Will get executed successfully leaving the output “deduction for customer”Will lead to run time ambiguity as the interface’s static method is overridden
Question
public interface Deduction { static void deduct() { System.out.println("deduct"); }}public class Customer implements Deduction { public static void deduct() { System.out.println("deduction for customer"); }}public class TechSol { public static void main(String[] args) { Deduction deduction = new Customer(); deduction.deduct(); }}What will happen when the code is subjected to compilation and execution? The code will not get compiled as the static method of interface is not accessed using interface nameWill get executed successfully leaving the output “deduct”Will get executed successfully leaving the output “deduction for customer”Will lead to run time ambiguity as the interface’s static method is overridden
Solution
The code will not get compiled as the static method of interface is not accessed using interface name.
In Java, static methods in an interface are not inherited by classes that implement the interface, so they must be accessed statically, i.e., InterfaceName.staticMethodName(). In this case, the static method deduct() of the interface Deduction is not accessed using the interface name, which leads to a compilation error.
So, the correct answer is "The code will not get compiled as the static method of interface is not accessed using interface name".
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