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What will be the output of the following code snippet?public class MyClass {    static int value = 10;      public void printValue() {        System.out.println(value);    }        public static void main(String[] args) {        MyClass obj = new MyClass();        obj.printValue();    }}Question 4Answera.0b.10c.Compilation errord.Runtime exception

Question

What will be the output of the following code snippet?public class MyClass {    static int value = 10;      public void printValue() {        System.out.println(value);    }        public static void main(String[] args) {        MyClass obj = new MyClass();        obj.printValue();    }}Question 4Answera.0b.10c.Compilation errord.Runtime exception

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Solution

The output of the code snippet will be 10.

Here's the step by step explanation:

  1. A class named MyClass is defined.
  2. Inside MyClass, a static integer variable value is declared and initialized with the value 10.
  3. A non-static method printValue() is defined which prints the value of the static variable value.
  4. In the main method, an object obj of MyClass is created.
  5. Using the object obj, the method printValue() is called. Since printValue() prints the value of the static variable value, and value is 10, 10 is printed.

So, the correct answer is b.10.

This problem has been solved

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