What will be the output of the following program? Write the answer in digits not alphabets.#include<stdio.h> int main() {     float i=10, *j;     void *k;     k=&i;     j=k;     printf("%.2f", *j);     return 0; }

The output of the program will be 10.00.

Here's the step by step explanation:

1. A float variable i is declared and initialized with the value 10.
2. A float pointer j and a void pointer k are declared.
3. The address of i is assigned to the void pointer k.
4. The void pointer k is assigned to the float pointer j. This is possible because a void pointer can hold the address of any data type.
5. The value at the address held by j is printed, which is the value of i, i.e., 10.00. The "%.2f" in the printf statement is used to print the float value up to 2 decimal places.