An 8 kg mass is placed at y = 3m. Where should a 10 kg mass be placed along the y axis so that the centre of mass will be located at 4.5 m?*1 point0.57 m5.7 m7.5 m57 m
Question
An 8 kg mass is placed at y = 3m. Where should a 10 kg mass be placed along the y axis so that the centre of mass will be located at 4.5 m?*1 point0.57 m5.7 m7.5 m57 m
Solution
The center of mass (CM) for a system of particles is given by the formula:
CM = (m1y1 + m2y2) / (m1 + m2)
where m1 and m2 are the masses of the particles and y1 and y2 are their respective positions along the y-axis.
In this case, we know that m1 = 8 kg, y1 = 3 m, m2 = 10 kg, and we want the CM to be at 4.5 m. We can plug these values into the formula and solve for y2:
4.5 = (83 + 10y2) / (8 + 10)
Solving this equation for y2 gives y2 = 5.7 m. So, the 10 kg mass should be placed at y = 5.7 m.
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