Two bodies of masses 0.5 kg and 1 kg are lying in the X-Y plane at points (-1, 2) and (3,4) respectively. Locate the center of mass of the system*1 point(1.67, 3.33)(3, 1)(3.33, 1.67)(16.7, 33.3)
Question
Two bodies of masses 0.5 kg and 1 kg are lying in the X-Y plane at points (-1, 2) and (3,4) respectively. Locate the center of mass of the system*1 point(1.67, 3.33)(3, 1)(3.33, 1.67)(16.7, 33.3)
Solution
The center of mass of a system of particles can be found using the formula:
Xcm = (m1x1 + m2x2) / (m1 + m2) Ycm = (m1y1 + m2y2) / (m1 + m2)
where m1 and m2 are the masses of the particles and (x1, y1) and (x2, y2) are their respective coordinates.
Here, m1 = 0.5 kg, m2 = 1 kg, (x1, y1) = (-1, 2) and (x2, y2) = (3, 4).
Substituting these values into the formula, we get:
Xcm = (0.5*-1 + 13) / (0.5 + 1) = 1.67 Ycm = (0.52 + 1*4) / (0.5 + 1) = 3.33
So, the center of mass of the system is located at (1.67, 3.33).
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