Deduce the pH of the solution formed when sulfur trioxide (SO3) reacts with water.

Sulfur trioxide (SO3) reacts with water (H2O) to form sulfuric acid (H2SO4). The reaction is as follows:

SO3 + H2O → H2SO4

Sulfuric acid is a strong acid, which means it completely ionizes in water. The ionization of sulfuric acid in water is as follows:

H2SO4 → 2H+ + SO4^2-

The concentration of H+ ions determines the pH of the solution. Since sulfuric acid is a strong acid, the concentration of H+ ions will be high, resulting in a low pH.

Therefore, the pH of the solution formed when sulfur trioxide reacts with water will be less than 7, indicating that the solution is acidic.

To get the exact pH, you would need to know the molarity of the sulfuric acid solution. The pH is calculated as the negative logarithm (base 10) of the H+ ion concentration.

pH = -log[H+]

Without the exact molarity, we cannot calculate the exact pH. However, we can say that it will be a low pH due to the strong acidic nature of sulfuric acid.