Find the pH and [SO42-] of a 0.0050 M sulfuric acid solution

To find the pH and [SO42-] of a 0.0050 M sulfuric acid solution, we need to understand that sulfuric acid (H2SO4) is a strong acid and it ionizes completely in water.

Step 1: Calculate the concentration of H+ ions Since sulfuric acid is a diprotic acid, it can donate two H+ ions. Therefore, the concentration of H+ ions will be twice the concentration of the sulfuric acid solution. [H+] = 2 * 0.0050 M = 0.010 M

Step 2: Calculate the pH The pH is calculated using the formula pH = -log[H+]. pH = -log(0.010) = 2

Step 3: Calculate the concentration of SO42- ions Since sulfuric acid ionizes completely in water, the concentration of SO42- ions will be equal to the initial concentration of the sulfuric acid solution. [SO42-] = 0.0050 M

So, the pH of the solution is 2 and the concentration of SO42- is 0.0050 M.