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Solve the trigonometric equation4cos(2𝑡)+1=3to find the exact solution on the interval [0,𝜋2]. Give your answer in radians.

Question

Solve the trigonometric equation4cos(2𝑡)+1=3to find the exact solution on the interval [0,𝜋2]. Give your answer in radians.

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Solution 1

Sure, let's solve the trigonometric equation step by step.

The given equation is 4cos(2t) + 1 = 3.

Step 1: Subtract 1 from both sides of the equation to isolate the cosine function:

4cos(2t) = 3 - 1 4cos(2t) = 2

Step 2: Divide both sides of the equation by 4 to solve for cos(2t):

cos(2t) = 2/4 cos(2t) = 0.5

Step 3: Now, we need to find the angle whose cosine is 0.5. We know that cos(π/3) = 0.5 and cos(-π/3) = 0.5. But since we are looking for solutions in the interval [0, π/2], we only consider π/3.

So, 2t = π/3

Step 4: Divide both sides of the equation by 2 to solve for t:

t = π/6

So, the solution to the equation 4cos(2t) + 1 = 3 in the interval [0, π/2] is t = π/6.

This problem has been solved

Solution 2

Sure, let's solve the trigonometric equation step by step.

The given equation is 4cos(2t) + 1 = 3.

Step 1: Subtract 1 from both sides of the equation to isolate the cosine function:

4cos(2t) = 3 - 1, 4cos(2t) = 2.

Step 2: Divide both sides of the equation by 4 to solve for cos(2t):

cos(2t) = 2/4, cos(2t) = 0.5.

Step 3: Now, we need to find the value of 2t. The cosine function gives 0.5 at two points in the unit circle, π/3 and -π/3. But since we are looking for solutions in the interval [0, π/2], we only consider the positive solution:

2t = π/3.

Step 4: Finally, divide both sides of the equation by 2 to solve for t:

t = π/6.

So, the solution to the equation 4cos(2t) + 1 = 3 in the interval [0, π/2] is t = π/6.

This problem has been solved

Solution 3

Claro, aquí tienes la solución paso a paso:

  1. Comienza con la ecuación dada: 4cos(2t)+1=3 4\cos(2t) + 1 = 3

  2. Resta 1 de ambos lados de la ecuación: 4cos(2t)=2 4\cos(2t) = 2

  3. Divide ambos lados de la ecuación por 4: cos(2t)=24=12 \cos(2t) = \frac{2}{4} = \frac{1}{2}

  4. Ahora, encuentra los valores de 2t2t que satisfacen cos(2t)=12\cos(2t) = \frac{1}{2}. Sabemos que: cos(π3)=12 \cos\left(\frac{\pi}{3}\right) = \frac{1}{2}

    Entonces: 2t=π3 2t = \frac{\pi}{3}

  5. Divide ambos lados de la ecuación por 2 para encontrar tt: t=π6 t = \frac{\pi}{6}

  6. Verifica que la solución esté en el intervalo dado [0,π2][0, \frac{\pi}{2}]. En este caso, π6\frac{\pi}{6} está dentro del intervalo.

Por lo tanto, la solución exacta en el intervalo [0,π2][0, \frac{\pi}{2}] es: t=π6 t = \frac{\pi}{6}

This problem has been solved

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