Solve the trigonometric equation3sin(2𝑡)+4=1
Question
Solve the trigonometric equation3sin(2𝑡)+4=1
Solution
Sure, let's solve the trigonometric equation step by step.
The given equation is 3sin(2t) + 4 = 1.
Step 1: Subtract 4 from both sides of the equation to isolate the trigonometric function.
3sin(2t) = 1 - 4
3sin(2t) = -3
Step 2: Divide both sides of the equation by 3 to solve for sin(2t).
sin(2t) = -3/3
sin(2t) = -1
Step 3: Now, we need to find the value of 2t. The sine function equals -1 at 3π/2 + 2nπ, where n is an integer.
2t = 3π/2 + 2nπ
Step 4: Finally, divide both sides of the equation by 2 to solve for t.
t = (3π/2 + 2nπ) / 2
t = 3π/4 + nπ
So, the solutions to the equation are t = 3π/4 + nπ, where n is an integer.
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