A random sample of 30 students taking statistics at a community college found the student’s mean GPA to be 3.25. A 95% confidence interval for the mean GPA of all students taking statistics at this college was determined to be (3.07, 3.43). What is the margin of error for this confidence interval? 3.25 0.18 0.36 0.95

A survey of a random sample of 1,500 young Americans found that 87% had earned their high school diploma. Based on these results, the 95% confidence interval for the proportion of young Americans who have earned their high school diploma is (0.853,0.887) What is the margin of error for this confidence interval? 0.95 0.87 0.034 0.017

Compute the margin of error at a 95% confidence level. (Round final answer to 2 decimal places.)

A doctor randomly selected 90 out of 300 patients to take a fitness test.  The mean grade of the fitness test was 43.7 with  a standard deviation of 0.52.  Find the margin of error for the mean fitness grade.  Use the formula below where n is the sample size and s is the standard deviation, then round the answer to the nearest tenth.  Margin of Error = 2(sn√)

Calculate the margin of error and construct the confidence interval for the population mean using the Student's t-distribution (you may assume the population data is normally distributed).10:41 p.m.x̄ =36.4, n=43, s=17, 98% confidence

A 98% confidence interval is found to be (32, 42). What is the margin of error?A.10B.9.8C.4.9D.5SUBMITarrow_backPREVIOUS