Obtain the generating function for the sequence 02, 12,22, 32,42…..
Question
Obtain the generating function for the sequence 02, 12,22, 32,42…..
Solution
To obtain the generating function for the sequence 02, 12, 22, 32, 42..., we can follow these steps:
Step 1: Write down the sequence in a general form. The given sequence can be written as an = 10n + 2, where n is the position of the term in the sequence.
Step 2: Express the general form in terms of a variable. Let's use x as the variable to express the general form. So, an = 10n + 2 becomes an = 10x + 2.
Step 3: Write down the generating function. The generating function for the sequence can be written as G(x) = a0 + a1x + a2x^2 + a3x^3 + ..., where a0, a1, a2, a3, ... are the terms of the sequence.
Step 4: Substitute the general form into the generating function. Substituting the general form an = 10x + 2 into the generating function, we get: G(x) = (10(0) + 2) + (10(1) + 2)x + (10(2) + 2)x^2 + (10(3) + 2)x^3 + ...
Simplifying this expression, we have: G(x) = 2 + 12x + 22x^2 + 32x^3 + ...
Therefore, the generating function for the sequence 02, 12, 22, 32, 42... is G(x) = 2 + 12x + 22x^2 + 32x^3 + ...
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