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What will be the output of the program?public class SwitchTest { public static void main(String[] args) { System.out.println("value =" + switchIt(4)); } public static int switchIt(int x) { int j = 1; switch (x) { case l: j++; case 2: j++; case 3: j++; case 4: j++; case 5: j++; default: j++; } return j + x; } }value = 2value = 4value = 6value = 8

Question

What will be the output of the program?public class SwitchTest { public static void main(String[] args) { System.out.println("value =" + switchIt(4)); } public static int switchIt(int x) { int j = 1; switch (x) { case l: j++; case 2: j++; case 3: j++; case 4: j++; case 5: j++; default: j++; } return j + x; } }value = 2value = 4value = 6value = 8

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Solution

The output of the program will be "value = 10". Here's why:

The method switchIt(4) is called in the main method with 4 as an argument.

In the switchIt method, j is initially 1.

The switch statement checks the value of x, which is 4.

Since there is no break statement in any of the case blocks, the execution will fall through all the case blocks starting from case 4 to default.

So, j is incremented 3 times (once for case 4, once for case 5, and once for default), making j equal to 4.

Finally, the method returns j + x, which is 4 + 4 = 8.

So, the output of the program is "value = 8".

This problem has been solved

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