What will be the value of y after execution of switch statement?public class Test{ public static void main(String[] args){ int x = 3, y = 4; switch(x + 3){ case 6: y = 0; case 7: y = 1; default: y += 1; } }}1234
Question
What will be the value of y after execution of switch statement?public class Test{ public static void main(String[] args){ int x = 3, y = 4; switch(x + 3){ case 6: y = 0; case 7: y = 1; default: y += 1; } }}1234
Solution
The value of y will be 2 after the execution of the switch statement.
Here's the step by step explanation:
-
The switch statement evaluates the expression
x + 3, which equals to3 + 3 = 6. -
It then checks for the case that matches the value 6. It finds
case 6and executes the statementy = 0;. Now, y is 0. -
However, there is no break statement after
case 6, so it continues to execute the next case, which iscase 7. Butcase 7does not match the value 6, so it is skipped. -
Finally, it reaches the
defaultcase. Thedefaultcase is executed if no other case matches. Here, it executes the statementy += 1;, which is equivalent toy = y + 1;. Since y was 0, now y becomes0 + 1 = 1. -
After the switch statement, y is 1.
-
However, there is a mistake in the question. The
defaultcase should be executed only if no other case matches. But in this code, it is executed even aftercase 6matches. This is because there is nobreakstatement aftercase 6. If we add abreakstatement aftercase 6, then thedefaultcase will not be executed, and y will remain 0 after the switch statement. But as per the given code, y will be 1 after the switch statement.
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