Knowee
Questions
Features
Study Tools

A supersonic vehicle powered by a ramjet engine is cruising at a speed of1000 m/s. The ramjet engine burns hydrogen in a subsonic combustor to producethrust. The heat of combustion for hydrogen is 120 MJ/kg. The overall efficiencyof the engineo , defined as the ratio of propulsive power to the total heat releasein the combustor, is 40%. Taking acceleration due to gravity0 10g = m/s2, thespecific impulse of the engine is _____________ seconds.(round off to the nearest integer).

Question

A supersonic vehicle powered by a ramjet engine is cruising at a speed of1000 m/s. The ramjet engine burns hydrogen in a subsonic combustor to producethrust. The heat of combustion for hydrogen is 120 MJ/kg. The overall efficiencyof the engineo , defined as the ratio of propulsive power to the total heat releasein the combustor, is 40%. Taking acceleration due to gravity0 10g = m/s2, thespecific impulse of the engine is _____________ seconds.(round off to the nearest integer).

...expand
🧐 Not the exact question you are looking for?Go ask a question

Solution

To find the specific impulse of the engine, we need to use the given information.

First, let's calculate the total heat release in the combustor. The heat of combustion for hydrogen is given as 120 MJ/kg. Since we don't have the mass of hydrogen burned, we can assume a unit mass of 1 kg for simplicity. Therefore, the total heat release in the combustor is 120 MJ.

Next, we need to calculate the propulsive power. The overall efficiency of the engine is given as 40%. This means that 40% of the total heat release is converted into propulsive power. Therefore, the propulsive power is 0.4 times the total heat release, which is 0.4 * 120 MJ = 48 MJ.

Now, let's calculate the thrust produced by the engine. The propulsive power is equal to the thrust multiplied by the vehicle's speed. Therefore, we can rearrange the equation to find the thrust: thrust = propulsive power / speed. Plugging in the values, we get thrust = 48 MJ / 1000 m/s = 48,000 N.

Finally, we can calculate the specific impulse. The specific impulse is defined as the thrust divided by the rate of propellant consumption. Since we don't have the rate of propellant consumption, we can assume a unit mass flow rate of 1 kg/s for simplicity. Therefore, the specific impulse is equal to the thrust divided by the mass flow rate, which is 48,000 N / 1 kg/s = 48,000 s.

Rounding off to the nearest integer, the specific impulse of the engine is approximately 48,000 seconds.

This problem has been solved

Similar Questions

An unfueled 1 000-kg experimental rocket sled on level frictionless rails is loaded with 50 kg of propellant. It exhausts the propellant in a 20 s "burn." If the rocket, initially at rest, moves at 160 m/s after the burn, what impulse is experienced by the rocket sled?Select one:a.1.9 × 105 kg·m/sb.1.6 × 105 kg·m/sc.1.5 × 105 kg·m/sd.1.1 × 105 kg·m/s

A Heat Engine has a power output of 17.4 kW and rejects heat to a  heat sink at a rate of 2.69 MJ/minute. The Thermal Efficiency of this Engine is:Group of answer choices72%15%28.6%38.8%

Consider a rocket which has a mass of 2.10 x 106 kg at takeoff, and its engines produce a constant thrust of 3.1 x 107 N as it takes off vertically. Choose the best response for the three quantities below:a) the initial acceleration of the rocket;b) the time needed for the rocket to reach a speed of 50 m/s, assuming constant mass and thrust; andc) description of the actual acceleration and time needed to reach 50 m/s factoring in that as the rocket ascends, fuel is expelled and thus the mass decreases significantly.Group of answer choicesa) 𝑎𝑜=4.96𝑚/𝑠2b) 𝑡=10.1𝑠c) Assuming the rocket can produce a constant thrust force, F0, the gravitational force acting downward on the rocket will not change, so the net force acting on the rocket will be constant. So, the acceleration will remain constant as the rocket burns fuel and the time it would take to reach 50 m/s will still be about 10.1 seconds.a) 𝑎𝑜=4.96𝑚/𝑠2b) 𝑡=10.1𝑠c) Assuming the rocket can produce a constant thrust force, F0, the gravitational force acting downward on the rocket will become lessened due to the loss of mass and so the net force acting upward will become larger. So, the acceleration will will increase as the rocket burns fuel and the time it would take to reach 50 m/s will be less than 10.1 secondsa) 𝑎𝑜=14.8𝑚/𝑠2b) 𝑡=3.38𝑠c) Assuming the rocket can produce a constant thrust force, F0, the gravitational force acting downward on the rocket will not change, so the net force acting on the rocket will be constant. So, the acceleration will remain constant as the rocket burns fuel and the time it would take to reach 50 m/s will still be about 3.38 secondsa) 𝑎𝑜=14.8𝑚/𝑠2b) 𝑡=3.38𝑠c) Assuming the rocket can produce a constant thrust force, F0, the gravitational force acting downward on the rocket will become lessened due to the loss of mass and so the net force acting upward will become larger. So, the acceleration will will increase as the rocket burns fuel and the time it would take to reach 50 m/s will be less than 3.38 seconds

A heat engine with an efficiency of 25% takes 1400 J of heat from the high temperature heat source and does J of work in each cycle.

With a neat diagram explain the working principle of a rocketIn a rocket of mass 1000kg fuel is consumed at the rate of 40 kg/s.Calculate the velocity of the gas ejected from the rocket

1/1

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.