With a neat diagram explain the working principle of a rocketIn a rocket of mass 1000kg fuel is consumed at the rate of 40 kg/s.Calculate the velocity of the gas ejected from the rocket

The working principle of a rocket is based on Newton's third law of motion, which states that for every action, there is an equal and opposite reaction.

Here's a step-by-step explanation:

1. Fuel Combustion: The rocket's engines combust the fuel, which creates hot gas. This is the action.

2. Gas Ejection: The hot gas is then ejected out of the rocket at high speed. This is the reaction. The force of the gas being ejected downward propels the rocket upward.

3. Continuous Propulsion: As long as the rocket continues to combust fuel and eject gas, it will continue to move upward.

Now, let's calculate the velocity of the gas ejected from the rocket.

Given:

• Mass of the rocket (m) = 1000 kg
• Rate of fuel consumption (r) = 40 kg/s

We can use the rocket equation, which is derived from the conservation of momentum. The equation is:

v = u + (Isp * g0 * ln(m0 / m1))

where:

• v is the final velocity
• u is the initial velocity (which is 0 for a stationary rocket)
• Isp is the specific impulse (which is a measure of how effectively a rocket uses propellant or jet fuel)
• g0 is the standard gravity (9.81 m/s^2)
• m0 is the initial total mass, including propellant
• m1 is the final total mass

However, we don't have enough information to use this equation. We need the specific impulse of the rocket fuel, and we need to know the final mass of the rocket after some fuel has been consumed.

If we assume that the rocket's engines are providing a constant force (which is a simplification), we can use the equation F = ma, where F is force, m is mass, and a is acceleration. The force provided by the engines is equal to the rate of fuel consumption times the velocity of the ejected gas. So we have:

F = r * v

We can rearrange this equation to solve for v:

v = F / r

But again, we don't have enough information. We need to know the force provided by the rocket's engines.

In conclusion, we can't calculate the velocity of the gas ejected from the rocket with the information given.

The working principle of a rocket is based on Newton's third law of motion, which states that for every action, there is an equal and opposite reaction.

Here's a step-by-step explanation:

1. Fuel Combustion: The rocket's engines combust the fuel, which creates high-pressure and high-temperature gases.

2. Gas Ejection: These gases are then ejected out of the rocket at a high speed through a nozzle. This is the 'action'.

3. Rocket Propulsion: The force exerted by the ejected gases propels the rocket in the opposite direction. This is the 'reaction'. The rocket continues to move upwards as long as the engines are firing.

Now, let's calculate the velocity of the gas ejected from the rocket.

Given:

• Mass of the rocket (m) = 1000 kg
• Rate of fuel consumption (dm/dt) = -40 kg/s (negative because the mass of the rocket is decreasing)

According to the law of conservation of momentum, the total momentum before and after the fuel is ejected remains the same.

So, m * v = (m - dm) * (v + dv)

Where:

• v is the velocity of the rocket
• dv is the change in velocity of the rocket
• dm is the change in mass of the rocket

Assuming the rocket starts from rest, the initial velocity (v) is 0. So, the equation simplifies to:

0 = -dm * dv => dv = - (dm/m) * v

Integrating this equation will give us the velocity of the gas ejected from the rocket.

Please note that this is a simplified explanation and actual rocket propulsion involves more complex physics and engineering.