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A small rocket burns a mass 0.0520 kgkg of fuel per second, ejecting it as a gas with a velocity relative to the rocket of magnitude 1630 m/sm/s.Part AWhat is the thrust of the rocket?Express your answer in newtons.Activate to select the appropriates template from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeActivate to select the appropriates symbol from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeF𝐹 =

Question

A small rocket burns a mass 0.0520 kgkg of fuel per second, ejecting it as a gas with a velocity relative to the rocket of magnitude 1630 m/sm/s.Part AWhat is the thrust of the rocket?Express your answer in newtons.Activate to select the appropriates template from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeActivate to select the appropriates symbol from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeF𝐹 =

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Solution

The thrust of a rocket is given by the equation:

F = dm/dt * v

where: F is the thrust, dm/dt is the rate of change of mass (which is the mass of fuel burned per second), and v is the velocity of the gas relative to the rocket.

Given: dm/dt = 0.0520 kg/s (mass of fuel burned per second), v = 1630 m/s (velocity of the gas relative to the rocket).

Substituting these values into the equation gives:

F = 0.0520 kg/s * 1630 m/s = 84.76 N

So, the thrust of the rocket is 84.76 Newtons.

This problem has been solved

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