If 0.0244mol hydrochloric acid HCl is mixed with 0.0244mol of sodium hydroxide NaOH in a "coffee cup" calorimeter, calculate the temperature change of 90.4g of the resulting solution if the specific heat of the solution is 1.00cal·g°C and the quantity of heat released by the reaction is ×1.52103cal. Round your answer to 3 significant figures.
Question
If 0.0244mol hydrochloric acid HCl is mixed with 0.0244mol of sodium hydroxide NaOH in a "coffee cup" calorimeter, calculate the temperature change of 90.4g of the resulting solution if the specific heat of the solution is 1.00cal·g°C and the quantity of heat released by the reaction is ×1.52103cal. Round your answer to 3 significant figures.
Solution
The heat released by the reaction is given as 1.52103 cal. The specific heat (c) of the solution is given as 1.00 cal/g°C. The mass (m) of the solution is given as 90.4 g.
We can use the formula q = mcΔT, where q is the heat transferred, m is the mass, c is the specific heat, and ΔT is the change in temperature.
We can rearrange this formula to solve for ΔT: ΔT = q / (mc).
Substituting the given values into this formula gives us:
ΔT = 1.52103 cal / (90.4 g * 1.00 cal/g°C) = 0.0168 °C
So, the temperature change of the solution is 0.0168 °C, rounded to three significant figures.
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