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Magnesium metal reacts with hydrochloric acid according to Reaction 1.Mg(s) + 2 HCl(aq) → MgCl2(aq) + H2(g)Reaction 1During an experiment to measure the molar enthalpy ΔH° of Reaction 1, a student placed 100. mL of dilute HCl(aq) into a coffee cup calorimeter, as shown in Figure 1.Figure 1  Coffee cup calorimeterAfter monitoring the solution temperature for 1 min, 0.486 g of Mg(s) was then added to the solution inside the calorimeter and stirred while continuing to monitor the temperature until the Mg(s) was completely consumed.  The results of the experiment are shown on the graph in Figure 2.Figure 2  Graph of temperature versus time during the reaction of magnesium with hydrochloric acidAccording to the first law of thermodynamics, the heat produced (or consumed) by a reaction qrxn must be equal to the heat transferred to (or taken from) the surroundings (ie, the solution and the calorimeter), as expressed by Equation 1.−qrxn = qsurroundings = qsolution + qcalorimeterEquation 1 Question 41Based on the results of the calorimetry experiment described in the passage, the magnitude of the molar enthalpy ΔH° for Reaction 1 (in kJ/mol Mg) is closest to which of the following?  (Note: Assume that the HCl(aq) has a density of 1.0 g/mL and a specific heat capacity of 4.0 J/(g∙°C), and that qcalorimeter ≈ 0.)A.8.84B.18.2C.442D.844

Question

Magnesium metal reacts with hydrochloric acid according to Reaction 1.Mg(s) + 2 HCl(aq) → MgCl2(aq) + H2(g)Reaction 1During an experiment to measure the molar enthalpy ΔH° of Reaction 1, a student placed 100. mL of dilute HCl(aq) into a coffee cup calorimeter, as shown in Figure 1.Figure 1  Coffee cup calorimeterAfter monitoring the solution temperature for 1 min, 0.486 g of Mg(s) was then added to the solution inside the calorimeter and stirred while continuing to monitor the temperature until the Mg(s) was completely consumed.  The results of the experiment are shown on the graph in Figure 2.Figure 2  Graph of temperature versus time during the reaction of magnesium with hydrochloric acidAccording to the first law of thermodynamics, the heat produced (or consumed) by a reaction qrxn must be equal to the heat transferred to (or taken from) the surroundings (ie, the solution and the calorimeter), as expressed by Equation 1.−qrxn = qsurroundings = qsolution + qcalorimeterEquation 1 Question 41Based on the results of the calorimetry experiment described in the passage, the magnitude of the molar enthalpy ΔH° for Reaction 1 (in kJ/mol Mg) is closest to which of the following?  (Note: Assume that the HCl(aq) has a density of 1.0 g/mL and a specific heat capacity of 4.0 J/(g∙°C), and that qcalorimeter ≈ 0.)A.8.84B.18.2C.442D.844

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Solution 1

To solve this problem, we need to use the formula for heat transfer: q = mcΔT, where m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

From the problem, we know that the specific heat capacity of HCl(aq) is 4.0 J/(g∙°C), the volume of HCl(aq) is 100 mL, and its density is 1.0 g/mL. Therefore, the mass of HCl(aq) is 100 g.

We also know that the reaction is exothermic, so the heat of the reaction qrxn is negative. However, we are asked for the magnitude, so we will take the absolute value.

The change in temperature ΔT can be found from the graph in Figure 2, but it is not given in the problem. Let's assume that ΔT is T for the purpose of this explanation.

So, the heat transferred to the solution qsolution is:

qsolution = mcΔT = 100 g * 4.0 J/(g∙°C) * T = 400T J

The molar enthalpy ΔH

This problem has been solved

Solution 2

To solve this problem, we need to use the formula for heat transfer: q = mcΔT, where m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

From the problem, we know that the volume of HCl is 100 mL. Since the density of HCl is given as 1.0 g/mL, the mass of HCl is 100 g.

The specific heat capacity (c) of HCl is given as 4.0 J/(g∙°C).

The change in temperature (ΔT) can be found from the graph in Figure 2, which is not provided in the question. However, you would subtract the initial temperature from the final temperature to get ΔT.

Once you have ΔT, you can plug the values into the formula to find q (the heat transferred to the solution), which is equal to -qrxn (the heat produced by the reaction) according to Equation 1.

To find the molar enthalpy ΔH°, you would divide qrxn by the number of moles of Mg used in the reaction. The number of moles of Mg can be found by dividing the mass of Mg used (0.486 g) by the molar mass of Mg (24.31 g/mol).

Finally, since the question asks for the answer in kJ/mol, you would need to convert J to kJ by dividing by 1000.

Without the specific values from the graph, I can't provide a numerical answer. However, this is the process you would use to solve this problem.

This problem has been solved

Similar Questions

Experiment #1 (Known Reaction 1 above) Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g) will be carried out using calorimetry. A certain mass of Mg will be added to a certain volume of HCl. The AQUEOUS solution of HCl is very DILUTE so we will consider it WATER for our calculations.Once the Mg is placed in the HCl the t1 will be taken and once the reaction is over (the temperature stops changing) the t2 will be taken. Watch this video link for Experiment 1 and enter the data into the observation table. (4 marks) Mass of Mg 0.50 g Mass of HCl (mL=g) 100 g t1 22 oC t2 45 oC *** Remember HCl is going to be considered H2O CALCULATIONS FOR EXPERIMENT #1 Use the data above and calculate the molar enthalpy (ΔHx) of the reaction in terms of Mg. HINT you need to do the 2 steps for this calculation ΔH = mcΔt & ΔH = nΔHx and this answer will be your ΔH value for your KNOWN equation #1. The video mentions figuring out the Limiting Reagent but it is Mg that you are calculating in terms of. (6 marks) t2-t1=ΔH → 45-22=23

If 0.0244mol hydrochloric acid HCl is mixed with 0.0244mol of sodium hydroxide NaOH in a "coffee cup" calorimeter, calculate the temperature change of 90.4g of the resulting solution if the specific heat of the solution is 1.00cal·g°C and the quantity of heat released by the reaction is ×1.52103cal. Round your answer to 3 significant figures.

The reaction between magnesium and hydrochloric acid is exothermic, so it releases heat. This could be a problem for Gemma's investigation because temperature also affects reaction rate. The rise in temperature could, therefore, influence the outcome in addition to the independent variable, concentration.Describe one way that Gemma could deal with this problem to improve the validity of her experiment.

PURPOSE: The purpose of this lab is to determine the molar enthalpy of combustion (ΔHCOMB) of Magnesium. Mg + ½O2 → MgO This reaction is too dangerous to carry out directly to measure the enthalpy Dangers of Burning Magnesium. Instead of carrying out this target reaction directly we will be carrying out two of the known reactions (1 & 2) and the 3rd known reaction value is also too dangerous to carry out so its value is given. TARGET: Mg(s) + ½O2(g) → MgO(s) ΔH = KNOWN EQUATIONS: 1) Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g) ΔH = kJ 2) MgO(s) + 2HCl(aq) → MgCl2(aq) + H2O(l) ΔH = kJ 3) H2(g) + ½O2(g) → H2O(l) ΔH = -285.8 kJ Two experiments will be carried out using calorimetry to determine the ΔH for Reaction 1 & Reaction 2. EXPERIMENT # 1 Experiment #1 (Known Reaction 1 above) Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g) will be carried out using calorimetry. A certain mass of Mg will be added to a certain volume of HCl. The AQUEOUS solution of HCl is very DILUTE so we will consider it WATER for our calculations.Once the Mg is placed in the HCl the t1 will be taken and once the reaction is over (the temperature stops changing) the t2 will be taken. Watch this video link for Experiment 1 and enter the data into the observation table. (4 marks) Mass of Mg g Mass of HCl (mL=g) g t1 oC t2 oC *** Remember HCl is going to be considered H2O CALCULATIONS FOR EXPERIMENT #1 Use the data above and calculate the molar enthalpy (ΔHx) of the reaction in terms of Mg. HINT you need to do the 2 steps for this calculation ΔH = mcΔt & ΔH = nΔHx and this answer will be your ΔH value for your KNOWN equation #1. The video mentions figuring out the Limiting Reagent but it is Mg that you are calculating in terms of. (6 marks) EXPERIMENT # 2 Experiment #2 (Known Reaction 2 above) MgO(s) + 2HCl(aq) → MgCl2(aq) + H2O(l)will be carried out using calorimetry. A certain mass of MgO will be added to a certain volume of HCl. The AQUEOUS solution of HCl is very DILUTE so we will consider it WATER for our calculations.Once the MgO is placed in the HCl the t1 will be taken and once the reaction is over (the temperature stops changing) the t2 will be taken. Watch this video link for Experiment 2 and enter the data into the observation table. (4 marks) Mass of MgO g Mass of HCl (mL=g) g t1 oC t2 oC *** Remember HCl is going to be considered H2O CALCULATIONS FOR EXPERIMENT

Magnesium metal reacts with hydrochloric acid. At the end of the reaction there is a small amount of magnesium left at the bottom of the flask. Which of the reactants was the limiting reactant?

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