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What will be the output of the following pseudocode?Integer a[5], b[5], c[5], k, lSet a[5] = {5, 9, 7, 3, 1}Set b[5] = {2, 4, 6, 8, 10}for(each k from 0 to 4)c[k] = a[k] - b[k]end forfor(each 1 from 0 to 4)Print c[1]end for

Question

What will be the output of the following pseudocode?Integer a[5], b[5], c[5], k, lSet a[5] = {5, 9, 7, 3, 1}Set b[5] = {2, 4, 6, 8, 10}for(each k from 0 to 4)c[k] = a[k] - b[k]end forfor(each 1 from 0 to 4)Print c[1]end for

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Solution

The pseudocode provided is performing an element-wise subtraction of two arrays 'a' and 'b' and storing the result in a third array 'c'. Then it prints the elements of array 'c'. Here is the step by step execution:

  1. Initialize arrays 'a' and 'b' with given values.
  2. Initialize an empty array 'c'.
  3. For each index 'k' from 0 to 4, subtract the 'k'th element of 'b' from the 'k'th element of 'a' and store the result in the 'k'th element of 'c'.
  4. After the first loop, the array 'c' will be {3, 5, 1, -5, -9} (because 5-2=3, 9-4=5, 7-6=1, 3-8=-5, 1-10=-9).
  5. Then, for each index 'l' from 0 to 4, print the 'l'th element of 'c'.

However, there seems to be a typo in the second loop. It should be "for(each l from 0 to 4)" instead of "for(each 1 from 0 to 4)". And it should print 'c[l]' instead of 'c[1]'. If we follow the original pseudocode, it will print the second element of 'c' five times, which is 5.

If we correct the typo, the output will be the elements of 'c': 3, 5, 1, -5, -9.

This problem has been solved

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