What will be the output of the following pseudocode?Integer a[5], b[5], c[5], k, lSet a[5] = {5, 9, 7, 3, 1}Set b[5] = {2, 4, 6, 8, 10}for(each k from 0 to 4)c[k] = a[k] - b[k]end forfor(each 1 from 0 to 4)Print c[1]end for
Question
What will be the output of the following pseudocode?Integer a[5], b[5], c[5], k, lSet a[5] = {5, 9, 7, 3, 1}Set b[5] = {2, 4, 6, 8, 10}for(each k from 0 to 4)c[k] = a[k] - b[k]end forfor(each 1 from 0 to 4)Print c[1]end for
Solution
The pseudocode provided is performing an element-wise subtraction of two arrays 'a' and 'b' and storing the result in a third array 'c'. Then it prints the elements of array 'c'. Here is the step by step execution:
- Initialize arrays 'a' and 'b' with given values.
- Initialize an empty array 'c'.
- For each index 'k' from 0 to 4, subtract the 'k'th element of 'b' from the 'k'th element of 'a' and store the result in the 'k'th element of 'c'.
- After the first loop, the array 'c' will be {3, 5, 1, -5, -9} (because 5-2=3, 9-4=5, 7-6=1, 3-8=-5, 1-10=-9).
- Then, for each index 'l' from 0 to 4, print the 'l'th element of 'c'.
However, there seems to be a typo in the second loop. It should be "for(each l from 0 to 4)" instead of "for(each 1 from 0 to 4)". And it should print 'c[l]' instead of 'c[1]'. If we follow the original pseudocode, it will print the second element of 'c' five times, which is 5.
If we correct the typo, the output will be the elements of 'c': 3, 5, 1, -5, -9.
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