Question 10Tag to RevisitWhat will be the output of the following C code?1.     #include <stdio.h>2.     int main()3.     {4.         int a = 10;5.         double b = 5.6;6.         int c;7.         c = a + b;8.         printf("%d", c);9.     }

The output of the given C code will be 15.

Here's the step by step explanation:

1. The integer variable 'a' is declared and initialized with the value 10.
2. The double variable 'b' is declared and initialized with the value 5.6.
3. The integer variable 'c' is declared.
4. The sum of 'a' and 'b' is calculated. Since 'b' is a double, the sum would be a double too. But since 'c' is an integer, the decimal part of the sum (0.6) will be truncated and only the integer part (15) will be stored in 'c'.
5. The value of 'c' is printed which is 15.