If 9A4157B is divisible by 88, then what is the value of A x B?Options :08415

The given number is 9A4157B. We know that a number is divisible by 88 if it is divisible by both 8 and 11 (since 88 is a product of 8 and 11).

1. For a number to be divisible by 8, the last three digits must be divisible by 8. So, 57B should be divisible by 8. The possible values of B that make 57B divisible by 8 are 2 and 6.

2. For a number to be divisible by 11, the difference between the sum of digits at odd places and the sum of digits at even places should be either 0 or a multiple of 11. So, (9+A+1+7) - (4+5+B) should be a multiple of 11. If B=2, the equation becomes (17+A) - (11+2) = 4+A which is not a multiple of 11 for any integer value of A. If B=6, the equation becomes (17+A) - (11+6) = A which is a multiple of 11 for A=0.

So, the possible values of A and B are 0 and 6 respectively. Therefore, A x B = 0 x 6 = 0. So, the answer is 0.