If a number 774958A96B is divisible by 8 and 9, the respectively values of A and B will beOptionsNone7 and 85 and 88 and 0

To find the values of A and B, we need to understand the divisibility rules of 8 and 9.

1. A number is divisible by 8 if the last three digits of the number form a number that is divisible by 8.
2. A number is divisible by 9 if the sum of its digits is divisible by 9.

Let's apply these rules to the number 774958A96B.

1. For the number to be divisible by 8, the last three digits (A96B) must form a number divisible by 8. The only possible values for A and B that satisfy this condition are A=5 and B=6.

2. For the number to be divisible by 9, the sum of its digits must be divisible by 9. If we add up the known digits, we get 7+7+4+9+5+8+9+6=55. If A=5 and B=6, the sum of the digits becomes 55+5+6=66, which is divisible by 9.

Therefore, the values of A and B that make the number 774958A96B divisible by both 8 and 9 are A=5 and B=6.