To solve the integral ∫(9e^x + sinx) dx, we can separate it into two integrals:

∫9e^x dx + ∫sinx dx

The integral of 9e^x dx is 9e^x + C1, where C1 is the constant of integration.

The integral of sinx dx is -cosx + C2, where C2 is the constant of integration.

So, the solution to the integral ∫(9e^x + sinx) dx is 9e^x - cosx + C, where C is the constant of integration (C1 + C2).

Question

To solve the integral ∫(9e^x + sinx) dx, we can separate it into two integrals:

∫9e^x dx + ∫sinx dx

The integral of 9e^x dx is 9e^x + C1, where C1 is the constant of integration.

The integral of sinx dx is -cosx + C2, where C2 is the constant of integration.

So, the solution to the integral ∫(9e^x + sinx) dx is 9e^x - cosx + C, where C is the constant of integration (C1 + C2).

Knowee AI · Accepted Answer

To solve the integral ∫(9e^x + sinx) dx, we can separate it into two integrals:

∫9e^x dx + ∫sinx dx

The integral of 9e^x dx is 9e^x + C1, where C1 is the constant of integration.

The integral of sinx dx is -cosx + C2, where C2 is the constant of integration.

So, the solution to the integral ∫(9e^x + sinx) dx is 9e^x - cosx + C, where C is the constant of integration (C1 + C2).

Find the ∫(9ex+sinx)dx