This problem can be solved by using Python's built-in functions for converting octal and hexadecimal numbers to decimal numbers. Here is a step-by-step solution:

1. First, we need to accept a number as input. In Python, we can use the `input()` function to do this. Let's call our input `num`.

```python
num = input()
```

2. Next, we need to check if the number starts with '0x' or '0'. In Python, we can use the `startswith()` method to do this.

```python
if num.startswith('0x'):
# This is a hexadecimal number
elif num.startswith('0'):
# This is an octal number
```

3. If the number is hexadecimal, we can convert it to decimal using Python's `int()` function with 16 as the second argument. If the number is octal, we can convert it to decimal using the `int()` function with 8 as the second argument.

```python
if num.startswith('0x'):
# This is a hexadecimal number
decimal = int(num, 16)
elif num.startswith('0'):
# This is an octal number
decimal = int(num, 8)
```

4. Finally, we print the decimal value.

```python
print(decimal)
```

So, the complete Python code would be:

```python
num = input()
if num.startswith('0x'):
# This is a hexadecimal number
decimal = int(num, 16)
elif num.startswith('0'):
# This is an octal number
decimal = int(num, 8)
print(decimal)
```

This code will convert the input octal or hexadecimal number to a decimal number and print it.

Question

This problem can be solved by using Python's built-in functions for converting octal and hexadecimal numbers to decimal numbers. Here is a step-by-step solution:

1. First, we need to accept a number as input. In Python, we can use the `input()` function to do this. Let's call our input `num`.

```python
num = input()
```

2. Next, we need to check if the number starts with '0x' or '0'. In Python, we can use the `startswith()` method to do this.

```python
if num.startswith('0x'):
    # This is a hexadecimal number
elif num.startswith('0'):
    # This is an octal number
```

3. If the number is hexadecimal, we can convert it to decimal using Python's `int()` function with 16 as the second argument. If the number is octal, we can convert it to decimal using the `int()` function with 8 as the second argument.

```python
if num.startswith('0x'):
    # This is a hexadecimal number
    decimal = int(num, 16)
elif num.startswith('0'):
    # This is an octal number
    decimal = int(num, 8)
```

4. Finally, we print the decimal value.

```python
print(decimal)
```

So, the complete Python code would be:

```python
num = input()
if num.startswith('0x'):
    # This is a hexadecimal number
    decimal = int(num, 16)
elif num.startswith('0'):
    # This is an octal number
    decimal = int(num, 8)
print(decimal)
```

This code will convert the input octal or hexadecimal number to a decimal number and print it.

Knowee AI · Accepted Answer