This problem is asking for a program that will convert an integer into its hexadecimal equivalent. Here's how you can do it:

Step 1: Get the input from the user. The input should be an integer.

Step 2: Convert the integer into a hexadecimal number. In Python, you can use the built-in function `hex()` to do this. This function takes an integer and returns a string that represents the hexadecimal equivalent of the given integer.

Step 3: Print the hexadecimal number. Note that the `hex()` function returns a string that starts with '0x' to indicate that it is a hexadecimal number. If you want to print the hexadecimal number without the '0x', you can use slicing to remove the first two characters of the string.

Here's a Python code snippet that implements these steps:

```python
# Step 1: Get the input from the user
inp = int(input())

# Step 2: Convert the integer into a hexadecimal number
hex_num = hex(inp)

# Step 3: Print the hexadecimal number without the '0x'
print(hex_num[2:])
```

For example, if the input is 100, the output will be '64'. If the input is 10245, the output will be '2805'.

Question

This problem is asking for a program that will convert an integer into its hexadecimal equivalent. Here's how you can do it:

Step 1: Get the input from the user. The input should be an integer.

Step 2: Convert the integer into a hexadecimal number. In Python, you can use the built-in function `hex()` to do this. This function takes an integer and returns a string that represents the hexadecimal equivalent of the given integer.

Step 3: Print the hexadecimal number. Note that the `hex()` function returns a string that starts with '0x' to indicate that it is a hexadecimal number. If you want to print the hexadecimal number without the '0x', you can use slicing to remove the first two characters of the string.

Here's a Python code snippet that implements these steps:

```python
# Step 1: Get the input from the user
inp = int(input())

# Step 2: Convert the integer into a hexadecimal number
hex_num = hex(inp)

# Step 3: Print the hexadecimal number without the '0x'
print(hex_num[2:])
```

For example, if the input is 100, the output will be '64'. If the input is 10245, the output will be '2805'.

Knowee AI · Accepted Answer

This problem is asking for a program that will convert an integer into its hexadecimal equivalent. Here's how you can do it:

Step 1: Get the input from the user. The input should be an integer.

Step 2: Convert the integer into a hexadecimal number. In Python, you can use the built-in function `hex()` to do this. This function takes an integer and returns a string that represents the hexadecimal equivalent of the given integer.

Step 3: Print the hexadecimal number. Note that the `hex()` function returns a string that starts with '0x' to indicate that it is a hexadecimal number. If you want to print the hexadecimal number without the '0x', you can use slicing to remove the first two characters of the string.

Here's a Python code snippet that implements these steps:

```python
# Step 1: Get the input from the user
inp = int(input())

# Step 2: Convert the integer into a hexadecimal number
hex_num = hex(inp)

# Step 3: Print the hexadecimal number without the '0x'
print(hex_num[2:])
```

For example, if the input is 100, the output will be '64'. If the input is 10245, the output will be '2805'.

Get a value and print its corresponding hexadecimal numberInput Format:Accept an integer as a inputOutput Format:Display the output in hexadecimal formatConstraints:1 <= inp<=10^16Sample Input 1:100Sample Output 1:64Sample Input 2:10245Sample Output 2:2805

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