Two trains are coming from opposite directions with speeds of 75 km/hr and 100 km/hr on two parallel tracks. At some moment the distance between them is 100 km. After T hours, distance between them is again 100 km. T is equal toA. 1 hrB. $$1{1} / {7}$$C. $$1{1} / {2}$$D. 2 hrsRecent Answer : Added by Clepina On 2022-08-14 18:01:55:1(1/7)hr
Question
Two trains are coming from opposite directions with speeds of 75 km/hr and 100 km/hr on two parallel tracks. At some moment the distance between them is 100 km. After T hours, distance between them is again 100 km. T is equal toA. 1 hrB. 1{1} / {7}C. 1{1} / {2}D. 2 hrsRecent Answer : Added by Clepina On 2022-08-14 18:01:55:1(1/7)hr
Solution
The problem is asking for the time it takes for two trains moving towards each other to be 100 km apart again after they first meet.
Step 1: Calculate the relative speed of the two trains. Since they are moving towards each other, their speeds are added together. So, the relative speed is 75 km/hr + 100 km/hr = 175 km/hr.
Step 2: The trains are initially 100 km apart. They meet each other and then move away from each other until they are 100 km apart again. This means they cover a total distance of 100 km (moving towards each other) + 100 km (moving away from each other) = 200 km.
Step 3: Time is calculated by dividing the total distance by the speed. So, T = 200 km / 175 km/hr = 1.14 hr.
Therefore, the time T is closest to 1.14 hours, which is approximately 1 hour and 8 minutes. This is closest to option B, 1 1/7 hours.
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